# Searching
# Getting the index for strings: str.index(), str.rindex() and str.find(), str.rfind()
String
also have an index
method but also more advanced options and the additional str.find
. For both of these there is a complementary reversed method.
astring = 'Hello on StackOverflow'
astring.index('o') # 4
astring.rindex('o') # 20
astring.find('o') # 4
astring.rfind('o') # 20
The difference between index
/rindex
and find
/rfind
is what happens if the substring is not found in the string:
astring.index('q') # ValueError: substring not found
astring.find('q') # -1
All of these methods allow a start and end index:
astring.index('o', 5) # 6
astring.index('o', 6) # 6 - start is inclusive
astring.index('o', 5, 7) # 6
astring.index('o', 5, 6) # - end is not inclusive
ValueError: substring not found
astring.rindex('o', 20) # 20
astring.rindex('o', 19) # 20 - still from left to right
astring.rindex('o', 4, 7) # 6
# Searching for an element
All built-in collections in Python implement a way to check element membership using in
.
# List
alist = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
5 in alist # True
10 in alist # False
# Tuple
atuple = ('0', '1', '2', '3', '4')
4 in atuple # False
'4' in atuple # True
# String
astring = 'i am a string'
'a' in astring # True
'am' in astring # True
'I' in astring # False
# Set
aset = {(10, 10), (20, 20), (30, 30)}
(10, 10) in aset # True
10 in aset # False
# Dict
dict
is a bit special: the normal in
only checks the keys. If you want to search in values you need to specify it. The same if you want to search for key-value pairs.
adict = {0: 'a', 1: 'b', 2: 'c', 3: 'd'}
1 in adict # True - implicitly searches in keys
'a' in adict # False
2 in adict.keys() # True - explicitly searches in keys
'a' in adict.values() # True - explicitly searches in values
(0, 'a') in adict.items() # True - explicitly searches key/value pairs
# Getting the index list and tuples: list.index(), tuple.index()
list
and tuple
have an index
-method to get the position of the element:
alist = [10, 16, 26, 5, 2, 19, 105, 26]
# search for 16 in the list
alist.index(16) # 1
alist[1] # 16
alist.index(15)
ValueError: 15 is not in list
But only returns the position of the first found element:
atuple = (10, 16, 26, 5, 2, 19, 105, 26)
atuple.index(26) # 2
atuple[2] # 26
atuple[7] # 26 - is also 26!
# Searching key(s) for a value in dict
dict
have no builtin method for searching a value or key because dictionaries are unordered. You can create a function that gets the key (or keys) for a specified value:
def getKeysForValue(dictionary, value):
foundkeys = []
for keys in dictionary:
if dictionary[key] == value:
foundkeys.append(key)
return foundkeys
This could also be written as an equivalent list comprehension:
def getKeysForValueComp(dictionary, value):
return [key for key in dictionary if dictionary[key] == value]
If you only care about one found key:
def getOneKeyForValue(dictionary, value):
return next(key for key in dictionary if dictionary[key] == value)
The first two functions will return a list
of all keys
that have the specified value:
adict = {'a': 10, 'b': 20, 'c': 10}
getKeysForValue(adict, 10) # ['c', 'a'] - order is random could as well be ['a', 'c']
getKeysForValueComp(adict, 10) # ['c', 'a'] - dito
getKeysForValueComp(adict, 20) # ['b']
getKeysForValueComp(adict, 25) # []
The other one will only return one key:
getOneKeyForValue(adict, 10) # 'c' - depending on the circumstances this could also be 'a'
getOneKeyForValue(adict, 20) # 'b'
and raise a StopIteration
-Exception
if the value is not in the dict
:
getOneKeyForValue(adict, 25)
StopIteration
# Getting the index for sorted sequences: bisect.bisect_left()
Sorted sequences allow the use of faster searching algorithms: bisect.bisect_left()
1 (opens new window):
import bisect
def index_sorted(sorted_seq, value):
"""Locate the leftmost value exactly equal to x or raise a ValueError"""
i = bisect.bisect_left(sorted_seq, value)
if i != len(sorted_seq) and sorted_seq[i] == value:
return i
raise ValueError
alist = [i for i in range(1, 100000, 3)] # Sorted list from 1 to 100000 with step 3
index_sorted(alist, 97285) # 32428
index_sorted(alist, 4) # 1
index_sorted(alist, 97286)
ValueError
For very large sorted sequences the speed gain can be quite high. In case for the first search approximatly 500 times as fast:
%timeit index_sorted(alist, 97285)
# 100000 loops, best of 3: 3 µs per loop
%timeit alist.index(97285)
# 1000 loops, best of 3: 1.58 ms per loop
While it's a bit slower if the element is one of the very first:
%timeit index_sorted(alist, 4)
# 100000 loops, best of 3: 2.98 µs per loop
%timeit alist.index(4)
# 1000000 loops, best of 3: 580 ns per loop
# Searching nested sequences
Searching in nested sequences like a list
of tuple
requires an approach like searching the keys for values in dict
but needs customized functions.
The index of the outermost sequence if the value was found in the sequence:
def outer_index(nested_sequence, value):
return next(index for index, inner in enumerate(nested_sequence)
for item in inner
if item == value)
alist_of_tuples = [(4, 5, 6), (3, 1, 'a'), (7, 0, 4.3)]
outer_index(alist_of_tuples, 'a') # 1
outer_index(alist_of_tuples, 4.3) # 2
or the index of the outer and inner sequence:
def outer_inner_index(nested_sequence, value):
return next((oindex, iindex) for oindex, inner in enumerate(nested_sequence)
for iindex, item in enumerate(inner)
if item == value)
outer_inner_index(alist_of_tuples, 'a') # (1, 2)
alist_of_tuples[1][2] # 'a'
outer_inner_index(alist_of_tuples, 7) # (2, 0)
alist_of_tuples[2][0] # 7
In general (not always) using next
and a generator expression with conditions to find the first occurrence of the searched value is the most efficient approach.
# Searching in custom classes: contains and iter
To allow the use of in
for custom classes the class must either provide the magic method __contains__
or, failing that, an __iter__
-method.
Suppose you have a class containing a list
of list
s:
class ListList:
def __init__(self, value):
self.value = value
# Create a set of all values for fast access
self.setofvalues = set(item for sublist in self.value for item in sublist)
def __iter__(self):
print('Using __iter__.')
# A generator over all sublist elements
return (item for sublist in self.value for item in sublist)
def __contains__(self, value):
print('Using __contains__.')
# Just lookup if the value is in the set
return value in self.setofvalues
# Even without the set you could use the iter method for the contains-check:
# return any(item == value for item in iter(self))
Using membership testing is possible using in
:
a = ListList([[1,1,1],[0,1,1],[1,5,1]])
10 in a # False
# Prints: Using __contains__.
5 in a # True
# Prints: Using __contains__.
even after deleting the __contains__
method:
del ListList.__contains__
5 in a # True
# Prints: Using __iter__.
Note: The looping in
(as in for i in a
) will always use __iter__
even if the class implements a __contains__
method.
# Remarks
All searching algorithms on iterables containing n
elements have O(n)
complexity. Only specialized algorithms like bisect.bisect_left()
can be faster with O(log(n))
complexity.