# List slicing (selecting parts of lists)
# Using the third "step" argument
lst = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']
lst[::2]
# Output: ['a', 'c', 'e', 'g']
lst[::3]
# Output: ['a', 'd', 'g']
# Selecting a sublist from a list
lst = ['a', 'b', 'c', 'd', 'e']
lst[2:4]
# Output: ['c', 'd']
lst[2:]
# Output: ['c', 'd', 'e']
lst[:4]
# Output: ['a', 'b', 'c', 'd']
# Reversing a list with slicing
a = [1, 2, 3, 4, 5]
# steps through the list backwards (step=-1)
b = a[::-1]
# built-in list method to reverse 'a'
a.reverse()
if a = b:
print(True)
print(b)
# Output:
# True
# [5, 4, 3, 2, 1]
# Shifting a list using slicing
def shift_list(array, s):
"""Shifts the elements of a list to the left or right.
Args:
array - the list to shift
s - the amount to shift the list ('+': right-shift, '-': left-shift)
Returns:
shifted_array - the shifted list
"""
# calculate actual shift amount (e.g., 11 --> 1 if length of the array is 5)
s %= len(array)
# reverse the shift direction to be more intuitive
s *= -1
# shift array with list slicing
shifted_array = array[s:] + array[:s]
return shifted_array
my_array = [1, 2, 3, 4, 5]
# negative numbers
shift_list(my_array, -7)
>>> [3, 4, 5, 1, 2]
# no shift on numbers equal to the size of the array
shift_list(my_array, 5)
>>> [1, 2, 3, 4, 5]
# works on positive numbers
shift_list(my_array, 3)
>>> [3, 4, 5, 1, 2]
# Syntax
- a[start:end] # items start through end-1
- a[start:] # items start through the rest of the array
- a[:end] # items from the beginning through end-1
- a[start🔚step] # start through not past end, by step
- a[:] # a copy of the whole array
- source (opens new window)
# Remarks
lst[::-1]
gives you a reversed copy of the liststart
orend
may be a negative number, which means it counts from the end of the array instead of the beginning. So:
a[-1] # last item in the array
a[-2:] # last two items in the array
a[:-2] # everything except the last two items