DevTut

# Bash Arithmetic

# Simple arithmetic with (( ))

#!/bin/bash
echo $(( 1 + 2 ))

Output: 3

# Using variables
#!/bin/bash
var1=4
var2=5
((output=$var1 * $var2))
printf "%d\n" "$output"

Output: 20

# Arithmetic command

  • let

   let num=1+2
    let num="1+2"
    let 'num= 1 + 2'
    let num=1 num+=2

You need quotes if there are spaces or globbing characters. So those will get error:


  let num = 1 + 2    #wrong
   let 'num = 1 + 2'  #right
   let a[1] = 1 + 1   #wrong
   let 'a[1] = 1 + 1' #right
  • (( ))

 ((a=$a+1))     #add 1 to a
  ((a = a + 1))  #like above
  ((a += 1))     #like above

We can use (()) in if. Some Example:

if (( a > 1 )); then echo "a is greater than 1"; fi

The output of (()) can be assigned to a variable:

result=$((a + 1))

Or used directly in output:

echo "The result of a + 1 is $((a + 1))"

# Simple arithmetic with expr

#!/bin/bash
expr 1 + 2

Output: 3

# Syntax

  • $(( EXPRESSION )) - Evaluates expression and returns its result.
  • expr EXPRESSION - Prints result of EXPRESSION to stdout.

    • # Parameters

    Parameter Details
    EXPRESSION Expression to evaluate

    # Remarks

    A space (" ") is required between each term (or sign) of the expression. "1+2" won't work, but "1 + 2" will work.

    ← Scoping →