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CASE

The CASE expression is used to implement if-then logic.

Use CASE to COUNT the number of rows in a column match a condition.

Section titled “Use CASE to COUNT the number of rows in a column match a condition.”

Use Case

CASE can be used in conjunction with SUM to return a count of only those items matching a pre-defined condition. (This is similar to COUNTIF in Excel.)

The trick is to return binary results indicating matches, so the “1”s returned for matching entries can be summed for a count of the total number of matches.

Given this table ItemSales, let’s say you want to learn the total number of items that have been categorized as “Expensive”:

IdItemIdPricePriceRating
110034.5EXPENSIVE
21452.3CHEAP
310034.5EXPENSIVE
410034.5EXPENSIVE
514510AFFORDABLE

Query

SELECT
COUNT(Id) AS ItemsCount,
SUM ( CASE
WHEN PriceRating = 'Expensive' THEN 1
ELSE 0
END
) AS ExpensiveItemsCount
FROM ItemSales

Results:

ItemsCountExpensiveItemsCount
53

Alternative:

SELECT
COUNT(Id) as ItemsCount,
SUM (
CASE PriceRating
WHEN 'Expensive' THEN 1
ELSE 0
END
) AS ExpensiveItemsCount
FROM ItemSales

Searched CASE in SELECT (Matches a boolean expression)

Section titled “Searched CASE in SELECT (Matches a boolean expression)”

The searched CASE returns results when a boolean expression is TRUE.

(This differs from the simple case, which can only check for equivalency with an input.)

SELECT Id, ItemId, Price,
CASE WHEN Price < 10 THEN 'CHEAP'
WHEN Price < 20 THEN 'AFFORDABLE'
ELSE 'EXPENSIVE'
END AS PriceRating
FROM ItemSales
IdItemIdPricePriceRating
110034.5EXPENSIVE
21452.3CHEAP
310034.5EXPENSIVE
410034.5EXPENSIVE
514510AFFORDABLE

We can use 1,2,3.. to determine the type of order:

SELECT * FROM DEPT
ORDER BY
CASE DEPARTMENT
WHEN 'MARKETING' THEN 1
WHEN 'SALES' THEN 2
WHEN 'RESEARCH' THEN 3
WHEN 'INNOVATION' THEN 4
ELSE 5
END,
CITY
IDREGIONCITYDEPARTMENTEMPLOYEES_NUMBER
12New EnglandBostonMARKETING9
15WestSan FranciscoMARKETING12
9MidwestChicagoSALES8
14Mid-AtlanticNew YorkSALES12
5WestLos AngelesRESEARCH11
10Mid-AtlanticPhiladelphiaRESEARCH13
4MidwestChicagoINNOVATION11
2MidwestDetroitHUMAN RESOURCES9

CASE’s shorthand variant evaluates an expression (usually a column) against a series of values. This variant is a bit shorter, and saves repeating the evaluated expression over and over again. The ELSE clause can still be used, though:

SELECT Id, ItemId, Price,
CASE Price WHEN 5 THEN 'CHEAP'
WHEN 15 THEN 'AFFORDABLE'
ELSE 'EXPENSIVE'
END as PriceRating
FROM ItemSales

A word of caution. It’s important to realize that when using the short variant the entire statement is evaluated at each WHEN. Therefore the following statement:

SELECT
CASE ABS(CHECKSUM(NEWID())) % 4
WHEN 0 THEN 'Dr'
WHEN 1 THEN 'Master'
WHEN 2 THEN 'Mr'
WHEN 3 THEN 'Mrs'
END

may produce a NULL result. That is because at each WHEN NEWID() is being called again with a new result. Equivalent to:

SELECT
CASE
WHEN ABS(CHECKSUM(NEWID())) % 4 = 0 THEN 'Dr'
WHEN ABS(CHECKSUM(NEWID())) % 4 = 1 THEN 'Master'
WHEN ABS(CHECKSUM(NEWID())) % 4 = 2 THEN 'Mr'
WHEN ABS(CHECKSUM(NEWID())) % 4 = 3 THEN 'Mrs'
END

Therefore it can miss all the WHEN cases and result as NULL.

sample on price increases:

UPDATE ItemPrice
SET Price = Price *
CASE ItemId
WHEN 1 THEN 1.05
WHEN 2 THEN 1.10
WHEN 3 THEN 1.15
ELSE 1.00
END

CASE use for NULL values ​​ordered last

Section titled “CASE use for NULL values ​​ordered last”

in this way ‘0’ representing the known values ​​are ranked first, ‘1’ representing the NULL values ​​are sorted by the last:

SELECT ID
,REGION
,CITY
,DEPARTMENT
,EMPLOYEES_NUMBER
FROM DEPT
ORDER BY
CASE WHEN REGION IS NULL THEN 1
ELSE 0
END,
REGION
IDREGIONCITYDEPARTMENTEMPLOYEES_NUMBER
10Mid-AtlanticPhiladelphiaRESEARCH13
14Mid-AtlanticNew YorkSALES12
9MidwestChicagoSALES8
12New EnglandBostonMARKETING9
5WestLos AngelesRESEARCH11
15NULLSan FranciscoMARKETING12
4NULLChicagoINNOVATION11
2NULLDetroitHUMAN RESOURCES9

CASE in ORDER BY clause to sort records by lowest value of 2 columns

Section titled “CASE in ORDER BY clause to sort records by lowest value of 2 columns”

Imagine that you need sort records by lowest value of either one of two columns. Some databases could use a non-aggregated MIN() or LEAST() function for this (... ORDER BY MIN(Date1, Date2)), but in standard SQL, you have to use a CASE expression.

The CASE expression in the query below looks at the Date1 and Date2 columns, checks which column has the lower value, and sorts the records depending on this value.

IdDate1Date2
12017-01-012017-01-31
22017-01-312017-01-03
32017-01-312017-01-02
42017-01-062017-01-31
52017-01-312017-01-05
62017-01-042017-01-31
SELECT Id, Date1, Date2
FROM YourTable
ORDER BY CASE
WHEN COALESCE(Date1, '1753-01-01') < COALESCE(Date2, '1753-01-01') THEN Date1
ELSE Date2
END
IdDate1Date2
12017-01-012017-01-31
32017-01-312017-01-02
22017-01-312017-01-03
62017-01-042017-01-31
52017-01-312017-01-05
42017-01-062017-01-31

As you see row with Id = 1 is first, that because Date1 have lowest record from entire table 2017-01-01, row where Id = 3 is second that because Date2 equals to 2017-01-02 that is second lowest value from table and so on.

So we have sorted records from 2017-01-01 to 2017-01-06 ascending and no care on which one column Date1 or Date2 are those values.

  • CASE input_expression
     WHEN compare1 THEN result1
    [WHEN compare2 THEN result2]...
    [ELSE resultX]
    END
  • CASE
     WHEN condition1 THEN result1
    [WHEN condition2 THEN result2]...
    [ELSE resultX]
    END
  • The simple CASE expression returns the first result whose compareX value is equal to the input_expression.

    The searched CASE expression returns the first result whose conditionX is true.