JSON in Sql Server
Format Query Results as JSON with FOR JSON
Section titled “Format Query Results as JSON with FOR JSON”Input table data (People table)
|Id|Name|Age |---|---|---|---|---|--- |1|John|23 |2|Jane|31
Query
SELECT Id, Name, AgeFROM PeopleFOR JSON PATHResult
[ {"Id":1,"Name":"John","Age":23}, {"Id":2,"Name":"Jane","Age":31}]Parse JSON text
Section titled “Parse JSON text”JSON_VALUE and JSON_QUERY functions parse JSON text and return scalar values or objects/arrays on the path in JSON text.
DECLARE @json NVARCHAR(100) = '{"id": 1, "user":{"name":"John"}, "skills":["C#","SQL"]}'
SELECT JSON_VALUE(@json, '$.id') AS Id, JSON_VALUE(@json, '$.user.name') AS Name, JSON_QUERY(@json, '$.user') AS UserObject, JSON_QUERY(@json, '$.skills') AS Skills, JSON_VALUE(@json, '$.skills[0]') AS Skill0Result
|Id|Name|UserObject|Skills|Skill0 |---|---|---|---|---|--- |1|John|{“name”:“John”}|[“C#”,“SQL”]|C#
Join parent and child JSON entities using CROSS APPLY OPENJSON
Section titled “Join parent and child JSON entities using CROSS APPLY OPENJSON”Join parent objects with their child entities, for example we want a relational table of each person and their hobbies
DECLARE @json nvarchar(1000) =N'[ { "id":1, "user":{"name":"John"}, "hobbies":[ {"name": "Reading"}, {"name": "Surfing"} ] }, { "id":2, "user":{"name":"Jane"}, "hobbies":[ {"name": "Programming"}, {"name": "Running"} ] } ]'Query
SELECT JSON_VALUE(person.value, '$.id') as Id, JSON_VALUE(person.value, '$.user.name') as PersonName, JSON_VALUE(hobbies.value, '$.name') as HobbyFROM OPENJSON (@json) as person CROSS APPLY OPENJSON(person.value, '$.hobbies') as hobbiesAlternatively this query can be written using the WITH clause.
SELECT Id, person.PersonName, HobbyFROM OPENJSON (@json)WITH( Id int '$.id', PersonName nvarchar(100) '$.user.name', Hobbies nvarchar(max) '$.hobbies' AS JSON) as personCROSS APPLY OPENJSON(Hobbies)WITH( Hobby nvarchar(100) '$.name')Result
|Id|PersonName|Hobby |---|---|---|---|---|--- |1|John|Reading |1|John|Surfing |2|Jane|Programming |2|Jane|Running
Index on JSON properties by using computed columns
Section titled “Index on JSON properties by using computed columns”When storing JSON documents in SQL Server, We need to be able to efficiently filter and sort query results on properties of the JSON documents.
CREATE TABLE JsonTable( id int identity primary key, jsonInfo nvarchar(max), CONSTRAINT [Content should be formatted as JSON] CHECK (ISJSON(jsonInfo)>0))INSERT INTO JsonTableVALUES(N'{"Name":"John","Age":23}'),(N'{"Name":"Jane","Age":31}'),(N'{"Name":"Bob","Age":37}'),(N'{"Name":"Adam","Age":65}')GOGiven the above table If we want to find the row with the name = ‘Adam’, we would execute the following query.
SELECT *FROM JsonTable WhereJSON_VALUE(jsonInfo, '$.Name') = 'Adam'However this will require SQL server to perform a full table which on a large table is not efficent.
To speed this up we would like to add an index, however we cannot directly reference properties in the JSON document. The solution is to add a computed column on the JSON path $.Name, then add an index on the computed column.
ALTER TABLE JsonTableADD vName as JSON_VALUE(jsonInfo, '$.Name')
CREATE INDEX idx_nameON JsonTable(vName)Now when we execute the same query, instead of a full table scan SQL server uses an index to seek into the non-clustered index and find the rows that satisfy the specified conditions.
Note: For SQL server to use the index, you must create the computed column with the same expression that you plan to use in your queries - in this example JSON_VALUE(jsonInfo, '$.Name'), however you can also use the name of computed column vName
Format one table row as a single JSON object using FOR JSON
Section titled “Format one table row as a single JSON object using FOR JSON”WITHOUT_ARRAY_WRAPPER option in FOR JSON clause will remove array brackets from the JSON output. This is useful if you are returning single row in the query.
Note: this option will produce invalid JSON output if more than one row is returned.
Input table data (People table)
|Id|Name|Age |---|---|---|---|---|--- |1|John|23 |2|Jane|31
Query
SELECT Id, Name, AgeFROM PeopleWHERE Id = 1FOR JSON PATH, WITHOUT_ARRAY_WRAPPERResult
{"Id":1,"Name":"John","Age":23}Parse JSON text using OPENJSON function
Section titled “Parse JSON text using OPENJSON function”OPENJSON function parses JSON text and returns multiple outputs. Values that should be returned are specified using the paths defined in the WITH clause. If a path is not specified for some column, the column name is used as a path. This function casts returned values to the SQL types defined in the WITH clause. AS JSON option must be specified in the column definition if some object/array should be returned.
DECLARE @json NVARCHAR(100) = '{"id": 1, "user":{"name":"John"}, "skills":["C#","SQL"]}'
SELECT *FROM OPENJSON (@json) WITH(Id int '$.id', Name nvarchar(100) '$.user.name', UserObject nvarchar(max) '$.user' AS JSON, Skills nvarchar(max) '$.skills' AS JSON, Skill0 nvarchar(20) '$.skills[0]')Result
|Id|Name|UserObject|Skills|Skill0 |---|---|---|---|---|--- |1|John|{“name”:“John”}|[“C#”,“SQL”]|C#
Syntax
Section titled “Syntax”- JSON_VALUE(expression , path) — extract a scalar value from a JSON string.
- JSON_QUERY( expression [ , path ] ) — Extracts an object or an array from a JSON string.
- OPENJSON( jsonExpression [ , path ] ) — table-value function that parses JSON text and returns objects and properties in JSON as rows and columns.
- ISJSON( expression ) — Tests whether a string contains valid JSON.
- JSON_MODIFY( expression , path , newValue ) — Updates the value of a property in a JSON string and returns the updated JSON string.
Parameters
Section titled “Parameters”|Parameters|Details
|---|---|---|---|---|---
|expression|Typically the name of a variable or a column that contains JSON text.
|path|A JSON path expression that specifies the property to update. path has the following syntax: [append] [ lax | strict ] $.
Remarks
Section titled “Remarks”The OPENJSON function is only available under compatibility level 130. If your database compatibility level is lower than 130, SQL Server will not be able to find and execute OPENJSON function. Currently all Azure SQL databases are set to 120 by default. You can change the compatibility level of a database using the following command:
ALTER DATABASE <Database-Name-Here> SET COMPATIBILITY_LEVEL = 130